{"id":18496,"date":"2024-05-08T04:27:09","date_gmt":"2024-05-08T04:27:09","guid":{"rendered":"https:\/\/soicau3029.minhngocxoso.com\/?p=18496"},"modified":"2024-05-08T04:27:09","modified_gmt":"2024-05-08T04:27:09","slug":"tong-hop-cau-lo-cau-de-va-cach-soi-cau-lo-de-hom-nay-nhu-sau","status":"publish","type":"post","link":"https:\/\/lodepnhatmb.com\/tong-hop-cau-lo-cau-de-va-cach-soi-cau-lo-de-hom-nay-nhu-sau\/","title":{"rendered":"T\u1ed5ng h\u1ee3p C\u1ea7u l\u00f4 , C\u1ea7u \u0111\u1ec1 v\u00e0 C\u00e1ch soi c\u1ea7u l\u00f4 \u0111\u1ec1 h\u00f4m nay nh\u01b0 sau"},"content":{"rendered":"
V\u00f2ng l\u1eb7p b\u00f3ng \u00e2m d\u01b0\u01a1ng ng\u0169 h\u00e0nh<\/p>\n
\u1edf \u0111\u00e2y ch\u1ec9 c\u1ea7n quan t\u00e2m \u0111\u1ebfn s\u1ef1 T\u01b0\u01a1ng sinh:<\/p>\n
Kim = 2 M\u1ed9c = 5 H\u1ecfa = 3 Th\u1ee7y =1 Th\u1ed5 = 4<\/p>\n
Nh\u01b0 v\u1eady, chi\u1ebfu theo b\u00f3ng ta c\u00f3 : Kim=7 M\u1ed9c=0 H\u1ecfa=8 Th\u1ee7y=6 Th\u1ed5=9<\/p>\n
Kim -> M\u1ed9c -> H\u1ecfa -> Th\u1ee7y -> Th\u1ed5 -> Kim<\/p>\n
t\u1ee9c l\u00e0 : 2->5->3->1->4->2 v\u00e0 7->0->8->6->9->7<\/p>\n
A \u2013 Tr\u00ean c\u01a1 s\u1edf b\u00f3ng d\u01b0\u01a1ng ng\u01b0\u1eddi ta chia ra c\u00e1c b\u1ed9 s\u1ed1<\/p>\n
B\u1ed9 00 : 00 55 05 50<\/p>\n
B\u1ed9 01 : 01 10 06 60 15 51 56 65<\/p>\n
B\u1ed9 02 : 02 20 07 70 52 25 57 75<\/p>\n
B\u1ed9 03 : 03 30 08 80 53 35 58 85<\/p>\n
B\u1ed9 04 : 04 40 09 90 54 45 59 95<\/p>\n
B\u1ed9 11 : 11 66 16 61<\/p>\n
B\u1ed9 12 : 12 21 17 71 26 62 76 67<\/p>\n
B\u1ed9 13 : 13 31 18 81 36 63 68 86<\/p>\n
B\u1ed9 14 : 14 41 19 91 46 64 69 96<\/p>\n
B\u1ed9 22 : 22 77 27 72<\/p>\n
B\u1ed9 23 : 23 32 28 82 37 73 78 87<\/p>\n
B\u1ed9 24 : 24 42 29 92 47 74 79 97<\/p>\n
B\u1ed9 33 : 33 88 38 83<\/p>\n
B\u1ed9 34 : 34 43 39 93 48 84 89 98<\/p>\n
B\u1ed9 44 : 44 99 49 94<\/p>\n
B\u1ed9 k\u00e9p l\u1ec7ch : 05 50 16 61 27 72 38 83 49 94<\/p>\n
B\u1ed9 k\u00e9p b\u1eb1ng : 00 55 11 66 22 77 33 88 44 99<\/p>\n
B \u2013 Tr\u00ean c\u01a1 s\u1edf b\u00f3ng \u00e2m ta c\u00f3 kh\u00e1i ni\u1ec7m b\u1ed9 k\u00e9p \u00e2m:<\/p>\n
07 70 14 41 29 92 36 63 58 85<\/p>\n
C \u2013 C\u00e1c b\u1ed9 s\u1ed1 \u0111\u1eb7c bi\u1ec7t kh\u00e1c<\/p>\n
<\/p>\n
B\u1ed9 s\u00e1t k\u00e9p ( 18 con ) g\u1ed3m : 01 10 12 21 23 32 34 43 45 54 56 65 67 76 78 87 89 98<\/p>\n
Cao \u2013 th\u1ea5p, th\u1ea5p \u2013 cao c\u1ee7a \u0111\u1ea7u \u0111\u00edt 2, \u0111\u1ea7u \u0111\u00edt 7 (18 kon)<\/p>\n
070, 171, 272, 373, 474, 252, 262, 282, 292<\/p>\n
B\u1ed9 s\u1ed1 H\u1ed9p s\u1ed1 (20 kon)<\/p>\n
343, 353, 373, 393, 454, 474, 575, 494, 595, 797<\/p>\n
B\u1ed9 s\u1ed1 24 kon<\/p>\n
121, 181, 232, 272, 282, 292, 373, 383, 393, 787, 797, 898<\/p>\n
Ngo\u00e0i ra c\u00f2n c\u00f3 d\u00e0n \u0111\u1ec1 36 con : \u0111\u00edt ch\u1eb5n lo\u1ea1i k\u00e9p v\u00e0 \u0111\u00edt 0 ,hay d\u00e0n 36 con t\u1eeb<\/p>\n
33 -> 38 (33, 34, 35, 36, 37, 38)
\n43 -> 48
\n53 -> 58
\n63 -> 68
\n73 -> 78
\n83 -> 88<\/p>\n
Ch\u00fang ta th\u01b0\u1eddng nghe d\u00e2n l\u00f4 \u0111\u1ec1 ph\u00e1n \u0111\u1ec1 h\u00f4m nay t\u1ed5ng 4 hay ch\u1ea1m 4 \u2026m\u00e0 c\u00f3 nhi\u1ec1u anh em m\u1edbi theo h\u1ecdc ch\u01b0a hi\u1ec3u.<\/p>\n
V\u1eady t\u1ed5ng l\u00e0 k\u1ebft qu\u1ea3 c\u1ee7a hai s\u1ed1 cu\u1ed1i c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ed9ng v\u1edbi nhau l\u1ea5y h\u00e0ng \u0111\u01a1n v\u1ecb nh\u01b0 v\u1eady ta c\u00f3 10 t\u1ed5ng t\u01b0\u01a1ng \u1ee9ng v\u1edbi 10 s\u1ed1 t\u1eeb 0 \u0111\u1ebfn 9 c\u1ee7a d\u00e3y s\u1ed1 t\u1ef1 nhi\u00ean .<\/p>\n
Vd : Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t mi\u1ec1n b\u1eafc h\u00f4m qua ng\u00e0y 27\/5\/2011 l\u00e0 49870 ta c\u00f37 + 0 = 7 => t\u1ed5ng 7<\/p>\n<\/div>\n